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Queryable.Union 方法实现json格式的字符串合并
阅读量:4689 次
发布时间:2019-06-09

本文共 2967 字,大约阅读时间需要 9 分钟。

1.在数据库中以json字符串格式保存,如:[{"name":"张三","time":"8.592","area":"27.27033","conc":"4.12136"},{"name":"李四","time":"9.100","area":"56.21229","conc":"4.57692"}]

 

2.添加新内容后合并不相同的数据。如果name相同,以最新的数据替换原来的数据。

如:数据库中原保存的数据是[{"name":"张三","time":"8.592","area":"27.27033","conc":"4.12136"},{"name":"李四","time":"9.100","area":"56.21229","conc":"4.57692"}]

新加的数据为[{"name":"张三","time":"12","area":"27.70533","conc":"4.12136"},{"name":"王五","time":"4","area":"77","conc":"8.788"}]

 则替换后的数据为[{"name":"张三","time":"12","area":"27.70533","conc":"4.12136"},{"name":"王五","time":"4","area":"77","conc":"8.788"},{"name":"李四","time":"9.100","area":"56.21229","conc":"4.57692"}]

代码如下:

 

 

1         public void InsertOrUpdateOnlyItem(List
listLe) 2 { 3 var listLeInsert = new List
(); 4 var listLeUpdate = new List
(); 5 foreach (var le in listLe) 6 { 7 tblLims_Ana_LE_Import_Common model = le; 8 var own = CurrentRepository.Find(a => a.fldTaskID == model.fldTaskID 9 && a.fldBizCatID == model.fldBizCatID10 && a.fldItemCode == model.fldItemCode11 && a.fldNumber == model.fldNumber12 && a.fldSampleCode == model.fldSampleCode);13 if (own != null)14 {15 var ser = new JavaScriptSerializer();16 17 var listown = ser.Deserialize
>>(own.fldImportData); //原数据18 var listmodel = ser.Deserialize
>>(model.fldImportData); //新数据19 IEqualityComparer
> ec = new EntityComparer(); //自定义的比较类20 own.fldImportData = ser.Serialize(listmodel.Union(listown, ec)); //合并数据21 22 23 listLeUpdate.Add(own);24 }25 else26 {27 listLeInsert.Add(model);28 }29 }30 CurrentRepository.UpdateAll(listLeUpdate);31 CurrentRepository.InsertAll(listLeInsert);32 CurrentRepository.Save();33 }
View Code

tblLims_Ana_LE_Import_Common 为数据库中存数据的表

Union() 方法中用到的自定义比较类:

1     ///   2     /// 自定义比较类  3     ///   4     public class EntityComparer : IEqualityComparer
> 5 { 6 public bool Equals(Dictionary
x, Dictionary
y) 7 { 8 if (ReferenceEquals(x, y)) return true; 9 10 if (ReferenceEquals(x, null) || ReferenceEquals(y, null))11 return false;12 13 return x["name"] == y["name"]; //如果名称相同就不追加14 }15 16 public int GetHashCode(Dictionary
obj)17 {18 if (ReferenceEquals(obj, null)) return 0;19 int hashName = obj["name"] == null ? 0 : obj["name"].GetHashCode();20 int hashCode = obj["name"] == null ? 0 : obj["name"].GetHashCode();21 return hashName ^ hashCode;22 }23 }
View Code

 

转载于:https://www.cnblogs.com/kaka8384/p/3367827.html

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